JSSC JTGLCCE Recruitment2026 Notification: The Jharkhand Staff Selection Commission (JSSC) has released the notification of JSSC JTGLCCE Recruitment 2026 for 611 posts on its official website. For this eligible candidates can apply online from 15 June to 14 July 2026 on the official website. We will give you complete information about this recruitment below.
The official notification of recruitment was released on 14 June 2026, which can be downloaded from the link given below. Please visit www.SarkariJobHubs.com regularly for the Latest Govt Job 2026, 12th Pass Jobs. All details related to this recruitment like notification, qualification, age limit, eligibility, result, previous papers, online, how to apply, exam date, answer key, syllabus and admit card important dates, application fee, salary, etc are given below.
Junior Scientific Assistant : Graduate / Post Graduate qualification in Science, Pharmacy, or Pharmaceutical Chemistry with the Relevant Experience.
Laboratory Assistant (Physics) : Graduate with Honours in Physics.
Laboratory Assistant (Chemistry) : Graduate with Honours in Chemistry.
For More Information Read the official notification.
How to Apply for JSSC JTGLCCE Recruitment 2026
Candidates who are eligible and interested in this recruitment can apply online by following the following procedure-
To apply, first visit the official website, the direct link of which is available in the table.
While applying, keep the necessary documents like mark sheet, identity card, address details, photograph, signature, ID proof like Aadhar card/PAN card, etc. with you.
Candidates first click on the apply online link given below.
After opening the page, first register, and then after receiving the ID and password, log in and give the required information for the application.
After this, fill out the given form carefully.
If any fee is asked from your category then pay it.
After this, submit the application form finally and take a printout.